Question 1067133
The width of a rectangle is 5 yards less than the length.
----
{{{w=L-5}}}


{{{A=wL}}}
{{{A=(L-5)L}}}



 If the width were decreased by 2 yards the area would be decreased by 50 square yard. 
----
Old area {{{L(L-5)}}}


New area  {{{L(L-5-2)}}}
{{{L(L-7)}}}



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Find the length and width of the original rectangle.
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{{{L(L-5)-L(L-7)=50}}}


{{{L^2-5L-(L^2-7L)=50}}}


{{{L^2-5L-L^2+7L=50}}}

{{{2L=50}}}

{{{highlight(L=25)}}}

Return to given description for w.
{{{w=L-5}}}


{{{w=25-5}}}


{{{highlight(w=20)}}}