Question 1067029
The points A(8,4) is on the circle that is tangent to the line 3y-4x-11=0 
at B(1,5). Find the equation of the circle. Where does it cut the x-axis? 
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Find the PB (perpendicular bisector) of AB.  
The center of the circle is on that line.
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Find the equation of the line perpendicular to the given line thru B.
The center of the circle is on that line.
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Find the intersection of the 2 lines --> center C (h,k).
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The radius r is the distance AC or BC.
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{{{(x-h)^2 + (y-k)^2 = r^2}}}