Question 1066999
If you REALLY have y=1/x+2, then {{{y=1/x+2}}},


{{{graph(300,300,-6,6,-6,6,1/x+2)}}}



If you have y=1/(x+2), then this is {{{y=1/(x+2)}}}, and  as graphed 

{{{graph(300,300,-6,6,-6,6,1/(x+2))}}}