Question 1066946
Helps to draw this:
If the ladder is x, the vertical distance from the ground is x-11 and the other leg, horizontal, is 33, units in feet.
x^2=(x-11)^2+33^2=x^2-22x+121+1089
x^2 cancel
-22x+1210=0
-22x=-1210
x=55 ft, ladder's length
it is a 33-44-55 right triangle, which is 11 x a 3-4-5 triangle

If the ladder is x and the distance from the ground is x-1 and the distance from the building is 3 feet.
x^2=(x-1)^2+3^2=x^2-2x+1+9
x^2 on each side cancel
-2x+10=0
2x=10
x=5 feet ladder
3 feet from building
leans 4 feet up the building
3-4-5 right triangle.