Question 1066936
 An object is thrown upward from the top of a 160​-foot building with an initial velocity of 144 feet per second.
 The height h of the object after t seconds is given by the quadratic equation h= −16t^2+144t+160.
 When will the object hit the​ ground?
:
When the objects hits the ground, h=0 therefore we can write this:
-16t^2 + 144t + 160 = 0
Solve for t
We can simplify this, divide thru by -16, resulting in:
t^2 - 9t - 10t = 0
Factors easily to
(t-10)(t+1) = 0
The positive solution
t = 10 seconds is the time from thrown to hitting the ground