Question 1066744
r for radius
d for diameter
{{{r=d/2}}}



For VOLUME {{{v=(4/3)pi*(d/2)^3}}}


If diameter is increased three times, then new radius is {{{3d/2}}}.
New volume,  {{{v[n]=(4/3)pi*(3d/2)^3}}};


How do {{{v[n]}}} and v compare?
How is the new volume changed? Ratio of  {{{v[n]/v}}}?