Question 1066767
{{{x^2+(x+1)^2+(x+2)^2=50}}}, if the first integer is x.


{{{x^2+x^2+2x+1+x^2+4x+4=50}}}

{{{3x^2+6x+5=50}}}

{{{3x^2+6x-45=0}}}

{{{x^2+2x-15=0}}}


{{{(x+5)(x-3)=0}}}


Either x=-5  or x=3.  See which of them works, or if both work.


{{{3^3+4^2+5^2}}}=50?
{{{9+16+25}}}
{{{25+25}}}
{{{50=50}}}
-
{{{(-5)^2+(-4)^2+(-3)^2}}}
{{{25+16+9}}}
same.
{{{50}}}


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ANSWER:  Either -5, -4, -3
OR
3, 4, 5
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