Question 13525
First, get the equation into standard form: {{{ax^2 + bx + c = 0}}}

{{{(x-2)^2 + x^2 = 0}}} Expand the parentheses.
{{{x^2 - 4x + 4 + x^2 = 0}}} Combine the x^2 terms.
{{{2x^2 - 4x + 4 = 0}}} Factor a 2.
{{{2(x^2 - 2x + 2) = 0}}} Solve the parentheses using the quadratic formula: {{{x = (-b+-sqrt(b^2-4ac))/2a}}}

{{{x=-(-2)+-sqrt((-2)^2-4(2))/2}}}
{{{x=(2+-sqrt(4-8))/2}}}
{{{x=1+-sqrt(-4)/2}}}
{{{x=1+-sqrt(-1)}}}
{{{x = 1+-i}}}