Question 1066361
Since the sine varies from 1 to -1, the
amplitude is {{{ 5*1 = 5 }}}
The period of the sine is {{{ 2*pi }}} radians
{{{ 3*theta = 2*pi }}}
{{{ theta = ( 2*pi )/3 }}} is the period of the function
The phase shift is {{{ pi/2 }}} radians
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Here's the plot:
{{{ graph( 400, 200, -1, 6, -6, 6, 5*sin( 3x + pi/2 )) }}} 
Notice the sine is shifted left by {{{ pi/2 }}}