Question 1066610
simplifying this
{{{y/(4-3i)}}}
multiply equation by the conjugate of the denominator over itself (same as multiplying by 1)
{{{y/(4-3i)}}}*{{{(4+3i)/(4+3i)}}} = {{{y(4+3i)/(16-9i^2)}}} = {{{(4y + 3yi)/(16 -9(-1))}}} = {{{(4y + 3yi)/(16 + 9)}}} = {{{(4y + 3yi)/25}}} or {{{(y(4+3i))/25}}}