Question 1066547
Let n be the smallest of the 3 consecutive even integers.

3n = (n+2) + (n+4)  

3n = 2n + 6
n = 6
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Ans: The 3 integers are  6, 8, and 10
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Check:
     "three times first" —>         3(6) = 18
     "sum of other two" —>        8+10 = 18  (ok)