Question 1066540
100h+10t+u, the original number


System of equations literally from the description:
{{{system(h+t+u=20,t=(1/4)(h+u),(100u+10t+h)-(u+10t+100h)=198)}}}



{{{system(h+t+u=20,4t=h+u,99u-99h=198)}}}
The first two equations of this revised system will quickly give you the tens placed digit:  {{{highlight(t=4)}}}......


Substitute for t=4 and revise:


{{{h+u+4=20}}}
{{{h+u=16}}}
{{{u+h=16}}}


{{{system(99u-99h=198,u+h=16)}}}
Multiply this second equation by 99:


{{{system(99u-99h=198,99u+99h=1584)}}}
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ADD corresponding members
{{{198u=1782}}}


{{{highlight(u=9)}}}


(Deleting earlier posted results....)