Question 1066512
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[9^(3/2)]^(-2) = 9^[(3/2)*(-2)]
[9^(3/2)]^(-2) = 9^(-3)
[9^(3/2)]^(-2) = 1/(9^3)
[9^(3/2)]^(-2) = <font color=red size=4>1/729</font>
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