<PRE><B>Question 1066498</B>
.
&lt;pre&gt;
My dear, 

for polynomials with real coefficients,

complex zeroes ALWAYS go in pairs (complex number, conjugate complex number).

Since you are given complex root i = {{{sqrt(-1)}}}, the conjugate number -i is ALSO the root.

Therefore, your answer is -i: &quot;minus i&quot;.
&lt;/pre&gt;

On complex numbers see the lessons

&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;- &lt;A HREF=http://www.algebra.com/algebra/homework/complex/Complex-numbers-and-arithmetical-operations.lesson&gt;Complex numbers and arithmetic operations on them&lt;/A&gt;

&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;- &lt;A HREF=http://www.algebra.com/algebra/homework/complex/Complex-plane.lesson&gt;Complex plane&lt;/A&gt;

&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;- &lt;A HREF=http://www.algebra.com/algebra/homework/complex/Addition-and-subtraction-of-complex-numbers-in-complex-plane.lesson&gt;Addition and subtraction of complex numbers in complex plane&lt;/A&gt;

&amp;nbsp;&amp;nbsp;&amp;nbsp;&amp;nbsp;- &lt;A HREF=http://www.algebra.com/algebra/homework/complex/Multiplication-and-division-of-complex-numbers-in-complex-plane-.lesson&gt;Multiplication and division of complex numbers in complex plane&lt;/A&gt;

in this site.


</PRE>