Question 1066460
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In my geometry class we are learning about special right triangles. (30,60,90 and 45,45,90). 
I recently took a quiz over the information and I was stuck on one problem. 


<pre>
There is a 30,60,90 triangle, with the long leg as 10 square root three, and the short leg as X. The hypotenuse is y. 

The problem wanted you to solve for x and y. I tried using the rule of: 

            short leg= x, 
            long leg=x square root three, and 
            the hypotenuse= 2x.                     THIS RULE IS CORRECT.

Using that rule I got x as 10 and y as 20.          YOUR SOLUTION AND YOUR ANSWER ARE CORRECT.

Unfortunately this wasn't the right answer,         <<<---+++  This statement is WRONG.

and I was wondering if you could work through the problem, step by step to help me understand how to use the 30,60,90 rule 
and how it applies to this problem. 
</pre>

Your solution is correct.


Your answer is correct.