Question 1066428
this reference should help.
<a href = "http://home.windstream.net/okrebs/page43.html" target = "_blank">http://home.windstream.net/okrebs/page43.html</a>


start with y = x^2.


that looks like this:


<img src = "http://theo.x10hosting.com/2017/020101.jpg" alt="$$$" </>


shift it to the right 6 units.


that makes it y = (x-6)^2.


that looks like this:


<img src = "http://theo.x10hosting.com/2017/020102.jpg" alt="$$$" </>


raise it up 3 units.


that makes it y = (x-6)^2 + 3


that looks like this:


<img src = "http://theo.x10hosting.com/2017/020103.jpg" alt="$$$" </>


reflect it about the x-axis.


that makes it y = -((x-6)^2 + 3)


that looks like this:


<img src = "http://theo.x10hosting.com/2017/020104.jpg" alt="$$$" </>


(x,y) = (-2,19) is not on the graph of the reflection about the x-axis.


if you reflected it about the y-axis, the equation would look like this:


y = ((-x)-6)^2 + 3)


that looks like this:


<img src = "http://theo.x10hosting.com/2017/020105.jpg" alt="$$$" </>


(-2,19) is on the reflection about the y-axis.


it is not on the reflection about the x-axis.


your solution is false.