Question 1066161

How many 2-digit numbers are there in which the sum of its digits drop to its previous half when you add a four to it.
<pre>If I understand this right, is this saying that when 4 is added to the number, the sum of its digits becomes {{{1/2}}} of the sum of the digits of the original number?
If so, then your number is: {{{highlight_green(28)}}}, since the sum of its digits is 10 (2 + 8), and when 4 is added to the number, the result is 32 (28 + 4), whose digits 
sum to 5 (3 + 2), and which is actually {{{1/2}}} of 2 + 8, or {{{1/2}}} of 10.