Question 1065957

Find three consecutive odd number such that 5 times the middle number is greater than the sum of the first and last number by 495. 
<pre>Let 1st number be F
Then middle and largest =  F + 2, and F + 4, respectively
We then get: 5(F + 2) = F + F + 4 + 495
5F + 10 = 2F + 499
5F - 2F = 499 - 10
3F = 489
F, or 1st = {{{highlight_green(matrix(1,3, 489/3, or, 163))}}}
You should be able to find the middle and largest!