Question 1065952
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  y^2\ -\ 6y\ =\ -6]


Put into standard form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  y^2\ -\ 6y\ +\ 6\ =\ 0]


Put the coefficients into the quadratic formula:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  y\ =\ \frac{-(-6)\ \pm\ \sqrt{(-6)^2\ -\ 4(1)(6)}}{2(1)}]


Do the arithmetic and simplify.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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