Question 1065943
H = 0.05x^2+2x−15​
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We are given H = 10 and asked to solve for x
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10 = 0.05x^2+2x−15​
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subtract 10 from both sides of =
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0.05x^2+2x−25 = 0
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Divide both sides of = by 0.05
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x^2 +40x -500 = 0
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(x + 50) * (x - 10) = 0
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x = -50 and x = 10
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We reject the negative value for x
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For a max height of 10 foot waves,
we have a wind speed of 10 knots
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