Question 13482
All you need to do is see if the x and y-coordinates of the given point satisfy the equation.  To do this, substitute the x-value (2) and the y-value (-3) from the point into the equation.

{{{3x - 6y + 1 = 0}}}
{{{3(2) - 6(-3) + 1 = 0}}}
{{{6 + 18 + 1 = 0}}}
{{{25 = 0}}} No, the equation is not satisfied by the coordinates of the given point so the point is not on the line defined by the equation.