Question 1065801
the sum of two numbers is 15. sum of its reciprocal is 103 . find the number
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sum of its reciprocal is 103 --- the 2 reciprocals?
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find the number --- which one of them?
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x + y = 15 --> y = 15-x
1/x + 1/y = 103 --> (x+y)/xy = 103
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(x+y)/xy = 103
Sub for y
15/(x*(15-x)) = 103
15 = 1545x - 103x^2
103x^2 - 1545x + 15 = 0
*[invoke solve_quadratic_equation 103,-1545,15]
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x = x1 value
y = x2 value
Or vice versa.