Question 1065801
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x + y = 15,       

{{{1/x + 1/y}}} = 103.   

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x + y = 15,

{{{(x+y)/xy}}} = 103.

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x + y = 15,

15/xy = 103,

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x + y = 15,

xy = {{{15/103}}}.

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x and y  are the roots of the quadratic equation

{{{x^2 -15x + 15/103}}} = 0.

Now you solve this quadratic equation and find its solutions.

They are your x and y.
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