Question 1065610
Looks like no real solutions.
.
.
.
*[illustration af11.JPG].
.
.
.
Here's why algebraically. 
The equations lead to,
{{{cos(A)=1/x}}}
{{{sin(A)=x^2}}}
And you know that,
{{{cos(A)^2+sin(A)^2=1}}}
{{{1/x^2+x^4=1}}}
The left hand side has a minimum value of y=1.89.
.
.
.
*[illustration af12.JPG].
.
.
.
So it will never equal 1, so there is no  real solution.