Question 1065588
If you are not sure, try each of them and see.


Addition will give you an imaginary component, and so will subtraction.


Multiplication?
{{{4-3i+2i-6i^2}}}
No.  You have the imaginary, {{{-i}}} as part of the number.


Division?
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{{{(4-3i)/(1+2i)}}}

{{{((4-3i)/(1+2i))((1-2i)/(1-2i))}}}, simply multiplication by 1

{{{(4-3i-8i+6i^2)/(1-4i^2)}}}------but you still will have an imaginary component in the numerator.
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You can also try the reciprocal and see what it will be, but...
You try it.
Unless this gives you a fully REAL result,  none of the choices will produce a real solution.