Question 1065563
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A train leaves Orlando at 4:00 PM. A second train leaves the same city in the same direction at 8:00{{{highlight(cross(8))}}} PM. 
The second train travels 112 mph faster than the first. If the second train overtakes the first at 10:00 PM, 
what is the speed of each of the two trains?
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<pre>
Let "v" be the speed of the first train, in mph.
Then the speed of the second train is (v+112) mph.

The equation for "t" is

6v = 2(v + 112).

6 in the left  is 6 hours from 4:00 pm to 10:00 pm (till overtaking moment).
2 in the right is 2 hours from 8:00 pm to 10:00 pm (till overtaking moment).

The solution is {{{(112*2/4)}}} = 56 mph.

<U>Answer</U>. First train speed is 56 mph. Second train speed is 56 + 112 = 168 mph.
</pre>

For more solved problems of this type see the lessons

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/travel/Travel-and-Distance-problems.lesson>Travel and Distance problems</A>  

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/travel/Typical-catching-up-Travel-and-Distance-problems.lesson>Typical catching up Travel and Distance problems</A>

in this site.



Also, you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lessons are the part of this textbook under the section "<U>Word problems</U>", the topic "<U>Travel and Distance problems</U>".