Question 1065458
So there are {{{2^8}}} or {{{256}}} possible answer combinations.
Only 1 is correct (no wrong answers).
Only 1 is completely wrong (all wrong answers).
You can look at the outcome as a binomial random variable to model the number of wrong answers.
{{{P(x)=C(8,x)*(0.5)^(x)*(0.5)^(8-x)=C(8,x)*0.5^8=C(8,x)/256}}}
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So from the table there are 8 out of 256 outcomes with 1 wrong (7 correct) and 28 out of 256 with 2 wrong (8 correct)