Question 1065509
(a - b)^2; = 5 and ab = 1, find the positive value of a + b.
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b = 1/a
(a - 1/a)^2 = 5
a - 1/a = sqrt(5)
a^2 - a*sqrt(5) - 1 = 0
*[invoke solve_quadratic_equation 1,-sqrt(5),-1]
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a = (3 + sqrt(5))/2
b = 2/(3+sqrt(5)) = (3-sqrt(5))/2
a + b = 3