Question 1065487
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A takes 30 minutes to reach a shop from his residence. B takes 20 minutes to reach the same shop from same residence. 
one day A departed to shop at 8a.m. if  B departed 5 minutes later. at what time B passes A?
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Let D be the distance from the residence to the shop.

A has the speed {{{D/30}}} units per minute, while B has the speed {{{D/20}}} units per minute.

Let "t" be the time counted from 8:05 am.

The distance for B is {{{t*(D/20)}}}.

The distance for A is {{{5*(D/30) + t*(D/30)}}}.

The equation for the time is

{{{t*(D/20)}}} = {{{5*(D/30) + t*(D/30)}}}.

Multiply everything by 60/D. You will get

3t = 5*2 + 2t,   or

3t - 2t = 10,

t = 10. 

<U>Answer</U>.  B passes A at 8:15 am.
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Solved.