Question 1065236
For a single die, the probability no 5 or 6 appears is (2/3)
For six of them, the probability is (2/3)^6=0.0878.
For a single die, the probability of one 5 is (1/6). The probability of no 6 is (5/6)^5. That is 0.0670.
There is the same probability of one 6 and no 5, 0.0670, and these three probabilities, which are not desired, is 0.2218.
Therefore, the probability of at least one 5 and one 6 is 0.7782.