Question 13456
That is correct!!
Now we have {{{x^2 - 5x=14}}}

Taking X common we have X(X-5) = 14
Factors of 14 are 7 and 2

Putting 7 on the L.H.S we get 7(7-2) = 14 = R.H.S.

Putting 2 on the L.H.S we get 2(2-5) = -14 which does not equal R.H.S

Putting -2 we get  -2(-2-5) = -2(-7) = 14 = R.H.S

So numbers can be either 7 or -2