Question 1065161
The second of three members are three times the first and the third is four more than one third the first.  the sum of this members is 43. find the three numbers
<pre>Let the 1st <s>members</s> number be F
Then 2nd is: 3F, and 3rd is: {{{matrix(1,5, T, "=", (1/3)F + 4, or, F/3 + 4)}}}	
We then get: {{{F + 3F + F/3 + 4 = 43}}}
{{{4F + F/3 = 39}}}	
12F + F = 117 ------- Multiplying by LCD, 3	
13F = 117
F, or 1st number = {{{highlight_green(117/13 = 9)}}}	
2nd number: {{{highlight_green(matrix(1,3, 3(9), or, 27))}}}
3rd number: {{{highlight_green(matrix(1,5, (1/3) * 9 + 4, or, 3 + 4, or, 7))}}}