<PRE><B>Question 1065161</B>
Let the members be represented by A, B, and C.
What do we know from the question?
A + B + C = 43
B = 3A
C = .33A + 4 
Substitute the values of the second two equations into the first.
A + B + C = 43
A + (3A) + (.33A+4) = 43
4A + .33A + 4 = 43
4.33A + 4 = 43
4.33A = 39
Divide.
A = 9 (disregard the insignificant places; due to rounding 1/3 to .33)
If we now know that A = 9, we can figure out the others.
B = 3A
B = 3(9)
B = 27
C = .33A + 4
C = 3 + 4
C = 7
Prove it by adding the values together.
9 + 27 + 7 = 43
Success!</PRE>