Question 1065132
Find the equation of the circle which passes through points (2,-2) and (3,4) and whose centre lies on the line x + y = 7 
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Find the equation of the line thru the 2 points.
The center of the circle in on the perpendicular bisector (PB) of that line.
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Find the intersection of the PB and the line x + y = 7.
That's the center (h,k).
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The radius r is the distance from the center to either point.
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{{{(x-h)^2 + (y-k)^2 = r^2}}} is the circle.
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