Question 1064951
2x^2-x+(1/8)=0
16x^2-8x+1=0
(4x-1)^2=0
x=(1/4); this is a "bounce" at (1/4).
{{{graph(300,300,-1,3,-10,10,2x^2-x+(1/8))}}}
Check: (1/4)^2=(1/16)
*2=(1/8)
-1/4=-1/8
+1/8=0