Question 93409
Add or Subtract as indicated. Express your result in simplest form.
3/x^2 + 4x + 3 - 1/x^2 - 9
:
Assume the problems is:
{{{3/((x^2 + 4x + 3))}}} - {{{1/((x^2 - 9))}}}
:
Factor:
{{{3/((x+3)(x+1))}}} - {{{1/((x+3)(x-3)))}}}
:
The common denominator: (x+3)(x+1)(x-3)
{{{(3(x-3) - 1(x+1))/(x+3)(x+1)(x-3)}}} = {{{(3x - 9 - x - 1)/(x+3)(x+1)(x-3)}}} = {{{(2x - 10)/(x+3)(x+1)(x-3)}}} = {{{(2(x - 5))/(x+3)(x+1)(x-3)}}}
:
That's about all you can do with it