<PRE><B>Question 1064852</B>
Write an equation for an alternating current that has a peak amplitude of 36.5 mA, a frequency of 30 Hz, and a phase angle of 63.5o. 
Round the numbers in your answer to 3 significant digits: 
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Form:: y = a*sin(b(x+(c/b))+d
amp = |a| = 36.5
freq = (360)/b = 30 implies that b = 12
phase = c/a = 63.5 implies c = 36.5*63.5 = 2317.75
d = 0
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Equation::
y = 36.5*sin(12(x+193.15))
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Cheers,
Stan H.
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