Question 93250
Solution:

 x - 3 )/( 4x - 3y )*( 16x2 - 9y2 )/( 3x2 - 5x - 12 ) ---------(1)

16x2 - 9y2 

this can be written in the form

( 4x )^2 -(3y)^2  [( a^2-b^2 = (a+b)(a-b))]

==> (4x-3y)(4x+3y)-----------(2)

consider  3x2 - 5x - 12 

Factorize : 3x^2-9x+4x-12
   
            3x(x-3)+4(x-3)

            (3x+4)(x-3)--------(3)

pluggin (2) and (3 )in (1)

(x - 3 )/( 4x - 3y *(4x-3y)(4x+3y)/(3x+4)(x-3)

(x-3) in the numerator and  in the denominator gets cancelled

(4x-3y) in the numerator and denominator gets cancelled

Now we have ,

4x+3y/3x+4

hence the solution