Question 1064870
Let n be the common denominator of the sweets each have. Then
4n+16:5n-2::3:1 So:
4n+16=3(5n-2)
4n+16=15n-6
11n=22
n=2
At the beginning, Abigail has 4n, or 8 sweets; and Ben has 5n, or 10.  Ben then eats 2 sweets, leaving him with 8. ☺☺☺☺