Question 93350
Solve the following system by graphing and algebraic methods

x 2 - y =3 

x - y =3
algebraic methods:

x^2 - y = 3 ---------(1)

x - y = 3 -----------(2)

 From equation (2) , we have

y = x- 3 

pluggin the value of y in equation (1)

x^2 -(x- 3) = 3

x^2 - x + 3 = 3

x^2 - x +3 -3 = 3-3

x^2 - x = 0

x(x-1) = 0 

x = 0 

x-1 = 0 

x -1+1 = 1

 x = 1

Hence x = 0 and x = 1 is the solution for the system of equation.


Graphic method
{{{ graph( 300, 200, -6, 5, -10, 10,y =  x^2 - 3 , y = x -3) }}}  

hene from the graph we can see that when x = 0 ,y= -3 and when x = 1 , y = -2