Question 1064627
{{{4^x+6/4^x=5}}}
Substituting,
{{{u+6/u=5}}}
{{{u^2+6=5u}}}
{{{u^2-5u+6=0}}}
{{{(u-3)(u-2)=0}}}
Two potential solutions:
{{{u-3=0}}}
{{{u=3}}}
{{{4^x=3}}}
{{{x=log(4,(3))}}}
{{{highlight(x=log((3))/log((4)))}}}
and
{{{u-2=0}}}
{{{u=2}}}
{{{4^x=2}}}
{{{highlight(x=1/2)}}}

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*[illustration asc3.JPG].