<PRE><B>Question 1064597</B>
Here is a table of the number of possible outcomes for each sum 3..18, condensed due to the symmetry of the possible outcomes:

&lt;pre&gt;
SUM                 n_ways                 SUM
 3                       1                  18
 4                       3                  17
 5                       6                  16 
 6                      10                  15
 7                      15                  14   
 8                      21                  13 
 9                      25                  12
10                      27                  11

The total possible outcomes is twice the sum of the middle column: 2*(1+3+6+10+15+21+25+27) = 216 (= 6x6x6)
&lt;/pre&gt;

To get 6 or less, we see that there are {{{ 1+3+6+10 = 20 }}} ways for that to happen.
Thus  Pr{ sum is 6 or less on 3 dice thrown } = {{{ highlight( 20/216) }}} or approx {{{highlight( 0.09259 )}}} 

</PRE>