Question 1064621
You choose an x, solve for y.
This is the equation of a straight line so you only need two points to graph it. 
So when {{{x=0}}},
{{{5(0)+3y=12}}}
{{{3y=12}}}
{{{y=4}}}
So ({{{0}}},{{{4}}}) is a point on the line.
When {{{x=1}}},
{{{5(1)+3y=12}}}
{{{5+3y=12}}}
{{{3y=7}}}
{{{y=7/3}}}
({{{1}}},{{{7/3}}})
Plot those two points and draw the straight line.
.
.
.
You could also use the x and y intercepts.
When {{{x=0}}},
{{{5(0)+3y=12}}}
{{{3y=12}}}
{{{y=4}}}
({{{0}}},{{{4}}})
When {{{y=0}}},
{{{5x+3(0)=12}}}
{{{5x=12}}}
{{{x=12/5}}}
({{{12/5}}},{{{0}}})
.
.
.
Either way you get the same line,
.
.
.
*[illustration asc1.JPG].
.
.
.