Question 92655
Given the inequality:
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{{{x + 11 > -5}}}
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You can work these following the same procedures as you do for equations with one exception. That 
exceptions is that if you ever have to multiply or divide both sides by a negative number, then
you also need to reverse the direction of the inequality sign.  In this problem you do not
need to use this rule.
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To solve this for x you need to get rid of the +11 on the left side. Do this by subtracting
11 from both sides. When you do that the inequality becomes:
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{{{x > -11 -5}}}
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On the right side you can combine the -11 and the -5 to get -16 and the inequality 
becomes:
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{{{x > -16}}}
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That means that x must be greater than -16.  You can translate this to mean that on a number 
line x can be any value that is to the right of the point -16. You show this by making a
point at -16 and you make the number line a heavy bar from the right of this point all the
way through 0 and on towards +infinity. Note that you must indicate that x cannot include
the point -16. Values of x must be to the right of -16.
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Hope this helps you to understand the problem.
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