Question 1064527
Conner tosses a dog treat upward with an initial velocity of 13.7 meters per second. The height of the treat above the dog's 'h' in meters after 't' seconds is given by h=13.7t-4.9t^2. 
If the dog doesn't jump, the dog catches the treat after about 2.8 seconds.
Solve for "h"::
h = 13.7*2.8 - 4.9*2.8^2  is approximately zero
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The maximum height the dog jumps is 9.6 meters.
How fast would Connor have to throw the dog treat in order to make it fly through the air for 6 seconds? 
Solve 9.6 = v*6 - 4.9*6^2
9.6 = 6v - 176.4
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6v = 186
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Ans: velocity = 31 ft/sec
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Cheers,
Stan H.
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