Question 1064501
The area of the square is,
{{{A[s]=(14x)^2=196x^2}}}
The area of the mirror is,
{{{A[cm]=pi(2x)^2=4pi*x^2}}},
.
.
{{{A[s]=A[f]+A[cm]}}}
So,
{{{A[f]=A[s]-A[cm]}}}
{{{A[f]=196x^2-4pi*x^2}}}
{{{A[f]=x^2(196-4pi)}}}