Question 1064149
All the energy is stored as potential energy,
{{{P=mgh}}}
{{{P=100000(9.8)(50)}}}
{{{P=4.9x10^7}}}{{{J}}}
.
.
.
So the difference in kinetic energy is transferred,
{{{KE=(1/2)mV^2}}}
{{{DELTA*KE=(1/2)(100000)(12^2-8^2)}}}
{{{DELTA*KE=5.95x10^6}}}{{{J}}}
So power would be KE per unit time,
{{{W=5.95x10^6/0.5=1.2x10^7}}}{{{watts}}}