<PRE><B>Question 1064281</B>
Ten percent of American truck drivers are women. Suppose 10 truck drivers are randomly selected to be interviewed about quality of work conditions, what is the probability that none will be women?
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10% of women;; 90% are men
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P(none of 10 are women) = p(all 10 are men) = 0.9^10 = 0.3487
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Cheers,
Stan H.
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