Question 1064358
Let n be the amount of money invested at 10% per year.  Then the remaining money is 22000-n. This gets split into two; being .5(22000-n) and another .5(22000-n). If she has $26400 after her first year, she has made 26400-22000=$4400 interest. So:
.1(n)+.02(.5(22000-n)+.4(.5(22000-n)=4400
4620-.11n=4400
.11n=220
n=2000
22000-n=20000
20000/2=10000
$2000 was invested at 10%; and $10000 was invested at 2% and 40% each. ☺☺☺☺