Question 1064409
When the general form is:
{{{ f(x) = a*x^2 + b*x + c }}}
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The formula for the vertex is:
{{{ x[v] = -b/(2a) }}}
{{{ a = -3 }}}
{{{ b = -6 }}}
{{{ x[v] = -(-6) / ( 2*(-3) ) }}}
{{{ x[v] = 6 / (-6) }}}
{{{ x[v] = -1 }}}
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Plug this result into the equation
{{{ f(-1) = -3*(-1)^2 - 6*(-1) - 2 }}}
{{{ f(-1) = -3 + 6 - 2 }}}
{{{ f(-1) = 1 }}}
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The vertex is at ( -1, 1 )
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The axis of symmetry is {{{ x = -1 }}}
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Here's the plot:

{{{ graph( 400, 400, -5, 5, -5, 5, -3x^2 - 6x - 2 ) }}}